(4x+3)(3x^2-14x-5)=0

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Solution for (4x+3)(3x^2-14x-5)=0 equation:


Simplifying
(4x + 3)(3x2 + -14x + -5) = 0

Reorder the terms:
(3 + 4x)(3x2 + -14x + -5) = 0

Reorder the terms:
(3 + 4x)(-5 + -14x + 3x2) = 0

Multiply (3 + 4x) * (-5 + -14x + 3x2)
(3(-5 + -14x + 3x2) + 4x * (-5 + -14x + 3x2)) = 0
((-5 * 3 + -14x * 3 + 3x2 * 3) + 4x * (-5 + -14x + 3x2)) = 0
((-15 + -42x + 9x2) + 4x * (-5 + -14x + 3x2)) = 0
(-15 + -42x + 9x2 + (-5 * 4x + -14x * 4x + 3x2 * 4x)) = 0
(-15 + -42x + 9x2 + (-20x + -56x2 + 12x3)) = 0

Reorder the terms:
(-15 + -42x + -20x + 9x2 + -56x2 + 12x3) = 0

Combine like terms: -42x + -20x = -62x
(-15 + -62x + 9x2 + -56x2 + 12x3) = 0

Combine like terms: 9x2 + -56x2 = -47x2
(-15 + -62x + -47x2 + 12x3) = 0

Solving
-15 + -62x + -47x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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